What is the kinetic energy of a 2-kilogram mass traveling at 3 meters/second?

What is the kinetic energy of a 2-kilogram mass traveling at 3 meters/second?

• A. 3 joules
• B. 6 joules
• C. 9 joules
• D. 18 joules

Answer: (C)

To determine the kinetic energy of an object, we use the formula for kinetic energy, which is expressed as: \[ KE = \frac{1}{2} m v^2 \] where \( KE \) represents kinetic energy, \( m \) is the mass of the object (in kilograms), and \( v \) is the velocity of the object (in meters per second). In this case, the mass \( m \) is given as 2 kilograms, and the velocity \( v \) is 3 meters/second. Plugging in these values into the formula gives: \[ KE = \frac{1}{2} \times 2 \, \text{kg} \times (3 \, \text{m/s})^2 \] \[ KE = \frac{1}{2} \times 2 \, \text{kg} \times 9 \, \text{m}^2/\text{s}^2 \] \[ KE = \frac{1}{2} \times 18 \, \text{kg m}^2/\text{s}^2 \] \[ KE = 9 \, \text{joules} \] Therefore, the kinetic energy

To determine the kinetic energy of an object, we use the formula for kinetic energy, which is expressed as:

[ KE = \frac{1}{2} m v^2 ]

where ( KE ) represents kinetic energy, ( m ) is the mass of the object (in kilograms), and ( v ) is the velocity of the object (in meters per second).

In this case, the mass ( m ) is given as 2 kilograms, and the velocity ( v ) is 3 meters/second. Plugging in these values into the formula gives:

[ KE = \frac{1}{2} \times 2 , \text{kg} \times (3 , \text{m/s})^2 ]

[ KE = \frac{1}{2} \times 2 , \text{kg} \times 9 , \text{m}^2/\text{s}^2 ]

[ KE = \frac{1}{2} \times 18 , \text{kg m}^2/\text{s}^2 ]

[ KE = 9 , \text{joules} ]

Therefore, the kinetic energy